Optimal. Leaf size=150 \[ -\frac{4 (A+4 C) \tan (c+d x)}{3 a^2 d}+\frac{(2 A+7 C) \tanh ^{-1}(\sin (c+d x))}{2 a^2 d}-\frac{2 (A+4 C) \tan (c+d x) \sec ^2(c+d x)}{3 a^2 d (\sec (c+d x)+1)}+\frac{(2 A+7 C) \tan (c+d x) \sec (c+d x)}{2 a^2 d}-\frac{(A+C) \tan (c+d x) \sec ^3(c+d x)}{3 d (a \sec (c+d x)+a)^2} \]
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Rubi [A] time = 0.305003, antiderivative size = 150, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.212, Rules used = {4085, 4019, 3787, 3767, 8, 3768, 3770} \[ -\frac{4 (A+4 C) \tan (c+d x)}{3 a^2 d}+\frac{(2 A+7 C) \tanh ^{-1}(\sin (c+d x))}{2 a^2 d}-\frac{2 (A+4 C) \tan (c+d x) \sec ^2(c+d x)}{3 a^2 d (\sec (c+d x)+1)}+\frac{(2 A+7 C) \tan (c+d x) \sec (c+d x)}{2 a^2 d}-\frac{(A+C) \tan (c+d x) \sec ^3(c+d x)}{3 d (a \sec (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 4085
Rule 4019
Rule 3787
Rule 3767
Rule 8
Rule 3768
Rule 3770
Rubi steps
\begin{align*} \int \frac{\sec ^3(c+d x) \left (A+C \sec ^2(c+d x)\right )}{(a+a \sec (c+d x))^2} \, dx &=-\frac{(A+C) \sec ^3(c+d x) \tan (c+d x)}{3 d (a+a \sec (c+d x))^2}-\frac{\int \frac{\sec ^3(c+d x) (3 a C-a (2 A+5 C) \sec (c+d x))}{a+a \sec (c+d x)} \, dx}{3 a^2}\\ &=-\frac{2 (A+4 C) \sec ^2(c+d x) \tan (c+d x)}{3 a^2 d (1+\sec (c+d x))}-\frac{(A+C) \sec ^3(c+d x) \tan (c+d x)}{3 d (a+a \sec (c+d x))^2}-\frac{\int \sec ^2(c+d x) \left (4 a^2 (A+4 C)-3 a^2 (2 A+7 C) \sec (c+d x)\right ) \, dx}{3 a^4}\\ &=-\frac{2 (A+4 C) \sec ^2(c+d x) \tan (c+d x)}{3 a^2 d (1+\sec (c+d x))}-\frac{(A+C) \sec ^3(c+d x) \tan (c+d x)}{3 d (a+a \sec (c+d x))^2}-\frac{(4 (A+4 C)) \int \sec ^2(c+d x) \, dx}{3 a^2}+\frac{(2 A+7 C) \int \sec ^3(c+d x) \, dx}{a^2}\\ &=\frac{(2 A+7 C) \sec (c+d x) \tan (c+d x)}{2 a^2 d}-\frac{2 (A+4 C) \sec ^2(c+d x) \tan (c+d x)}{3 a^2 d (1+\sec (c+d x))}-\frac{(A+C) \sec ^3(c+d x) \tan (c+d x)}{3 d (a+a \sec (c+d x))^2}+\frac{(2 A+7 C) \int \sec (c+d x) \, dx}{2 a^2}+\frac{(4 (A+4 C)) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 a^2 d}\\ &=\frac{(2 A+7 C) \tanh ^{-1}(\sin (c+d x))}{2 a^2 d}-\frac{4 (A+4 C) \tan (c+d x)}{3 a^2 d}+\frac{(2 A+7 C) \sec (c+d x) \tan (c+d x)}{2 a^2 d}-\frac{2 (A+4 C) \sec ^2(c+d x) \tan (c+d x)}{3 a^2 d (1+\sec (c+d x))}-\frac{(A+C) \sec ^3(c+d x) \tan (c+d x)}{3 d (a+a \sec (c+d x))^2}\\ \end{align*}
Mathematica [B] time = 2.11466, size = 513, normalized size = 3.42 \[ -\frac{\cos \left (\frac{1}{2} (c+d x)\right ) \left (A+C \sec ^2(c+d x)\right ) \left (\sec \left (\frac{c}{2}\right ) \sec (c) \sec ^2(c+d x) \left (-36 A \sin \left (c-\frac{d x}{2}\right )+36 A \sin \left (c+\frac{d x}{2}\right )-20 A \sin \left (2 c+\frac{d x}{2}\right )-18 A \sin \left (c+\frac{3 d x}{2}\right )+22 A \sin \left (2 c+\frac{3 d x}{2}\right )-18 A \sin \left (3 c+\frac{3 d x}{2}\right )+18 A \sin \left (c+\frac{5 d x}{2}\right )-6 A \sin \left (2 c+\frac{5 d x}{2}\right )+18 A \sin \left (3 c+\frac{5 d x}{2}\right )-6 A \sin \left (4 c+\frac{5 d x}{2}\right )+8 A \sin \left (2 c+\frac{7 d x}{2}\right )+8 A \sin \left (4 c+\frac{7 d x}{2}\right )-2 (10 A+7 C) \sin \left (\frac{d x}{2}\right )+(22 A+97 C) \sin \left (\frac{3 d x}{2}\right )-126 C \sin \left (c-\frac{d x}{2}\right )+42 C \sin \left (c+\frac{d x}{2}\right )-98 C \sin \left (2 c+\frac{d x}{2}\right )-3 C \sin \left (c+\frac{3 d x}{2}\right )+37 C \sin \left (2 c+\frac{3 d x}{2}\right )-63 C \sin \left (3 c+\frac{3 d x}{2}\right )+75 C \sin \left (c+\frac{5 d x}{2}\right )+15 C \sin \left (2 c+\frac{5 d x}{2}\right )+39 C \sin \left (3 c+\frac{5 d x}{2}\right )-21 C \sin \left (4 c+\frac{5 d x}{2}\right )+32 C \sin \left (2 c+\frac{7 d x}{2}\right )+12 C \sin \left (3 c+\frac{7 d x}{2}\right )+20 C \sin \left (4 c+\frac{7 d x}{2}\right )\right )+96 (2 A+7 C) \cos ^3\left (\frac{1}{2} (c+d x)\right ) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )\right )}{24 a^2 d (\sec (c+d x)+1)^2 (A \cos (2 (c+d x))+A+2 C)} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.069, size = 249, normalized size = 1.7 \begin{align*} -{\frac{A}{6\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}-{\frac{C}{6\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}-{\frac{3\,A}{2\,d{a}^{2}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{7\,C}{2\,d{a}^{2}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{A}{d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }+{\frac{7\,C}{2\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }-{\frac{C}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}}+{\frac{5\,C}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}-{\frac{A}{d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) }-{\frac{7\,C}{2\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) }+{\frac{C}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}+{\frac{5\,C}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.95685, size = 389, normalized size = 2.59 \begin{align*} -\frac{C{\left (\frac{6 \,{\left (\frac{3 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{5 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )}}{a^{2} - \frac{2 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}} + \frac{\frac{21 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{\sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}}{a^{2}} - \frac{21 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{2}} + \frac{21 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{2}}\right )} + A{\left (\frac{\frac{9 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{\sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}}{a^{2}} - \frac{6 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{2}} + \frac{6 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{2}}\right )}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.516834, size = 554, normalized size = 3.69 \begin{align*} \frac{3 \,{\left ({\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{4} + 2 \,{\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{3} +{\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left ({\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{4} + 2 \,{\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{3} +{\left (2 \, A + 7 \, C\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (8 \,{\left (A + 4 \, C\right )} \cos \left (d x + c\right )^{3} +{\left (10 \, A + 43 \, C\right )} \cos \left (d x + c\right )^{2} + 6 \, C \cos \left (d x + c\right ) - 3 \, C\right )} \sin \left (d x + c\right )}{12 \,{\left (a^{2} d \cos \left (d x + c\right )^{4} + 2 \, a^{2} d \cos \left (d x + c\right )^{3} + a^{2} d \cos \left (d x + c\right )^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{A \sec ^{3}{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx + \int \frac{C \sec ^{5}{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.25169, size = 231, normalized size = 1.54 \begin{align*} \frac{\frac{3 \,{\left (2 \, A + 7 \, C\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right )}{a^{2}} - \frac{3 \,{\left (2 \, A + 7 \, C\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right )}{a^{2}} + \frac{6 \,{\left (5 \, C \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 3 \, C \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{2} a^{2}} - \frac{A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + C a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 9 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 21 \, C a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{6}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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